document.write( "Question 965947: 1-Sin x=the square root of 2 cos x
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Algebra.Com's Answer #590398 by lwsshak3(11628)\"\" \"About 
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1-Sin x=the square root of 2 cos x
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\n" ); document.write( "for: (0, 360˚)
\n" ); document.write( "1-sinx=√2cosx
\n" ); document.write( "square both sides:
\n" ); document.write( "1-2sinx+sin^2(x)=2cos^2(x)
\n" ); document.write( "1-2sinx+sin^2(x)=2(1-sin^2(x)
\n" ); document.write( "1-2sinx+sin^2(x)=2-2sin^2(x)
\n" ); document.write( "3sin^2(x)-2sinx-1=0
\n" ); document.write( "(3sinx+1)(sinx-1)=0
\n" ); document.write( "..
\n" ); document.write( "3sinx+1=0
\n" ); document.write( "sinx=-1/3
\n" ); document.write( "x≈199.47˚, 340.53˚
\n" ); document.write( "or
\n" ); document.write( "sinx-1=0
\n" ); document.write( "sinx=1
\n" ); document.write( "x=90˚(reject, extraneous root)
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