document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=965961>Question 965961</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the logarithmic differentiation to differentiate the function\r<BR>\n" );
document.write( "\n" );
document.write( "y= &#8731;((x(x+1)(x-2))/((x^2-2)(2x+3)))\r<BR>\n" );
document.write( "\n" );
document.write( "with details please. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #590394 by </B><A HREF=/tutors/aboutme.mpl?userid=t0hierry><B>t0hierry(194)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=t0hierry><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=t0hierry><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=590394\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> logy = 1/3(log x + log(x+1) + log(x-2) - log(x^2-2) - log(2x+3))\r<BR>\n" );
document.write( "\n" );
document.write( "take derivative\r<BR>\n" );
document.write( "\n" );
document.write( "y'/y = 1/3 (1/x + 1/x+1 + 1/x-2 - 2x/x^2-2 - 2/2x + 3)\r<BR>\n" );
document.write( "\n" );
document.write( "y' = 1/3 (1/x + 1/x+1 + 1/x-2 - 2x/x^2-2 - 2/2x + 3) y\r<BR>\n" );
document.write( "\n" );
document.write( "where y= &#8731;((x(x+1)(x-2))/((x^2-2)(2x+3))) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );