document.write( "Question 965909: the braking distance between D in feet required to stop a car traveling x miles per hour on dry, level pavement can be approximated by D=1/16x^2\r
\n" ); document.write( "\n" ); document.write( "A. calculate the braking distance for 20 MPH\r
\n" ); document.write( "\n" ); document.write( "calculate the braking distance for 60 MPH.\r
\n" ); document.write( "\n" ); document.write( "(round to the nearest tenth)\r
\n" ); document.write( "\n" ); document.write( "B.if the braking distance is 25 feet, estimate the speed of the car\r
\n" ); document.write( "\n" ); document.write( "Estimated speed is approximately___ MPH\r
\n" ); document.write( "\n" ); document.write( "(round to the nearest whole number)\r
\n" ); document.write( "\n" ); document.write( "C. use a calculator to solve part (B) numerically.\r
\n" ); document.write( "\n" ); document.write( "estimated speed is approximately____MPH
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Algebra.Com's Answer #590349 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "For 20 mph:
\n" ); document.write( "\"D=%281%2F16%29x%5E2\"=\"%281%2F16%2920%5E2%29=1%2F16%28400%29\"=\"25ft\"
\n" ); document.write( "ANSWER 1: The braking distance at 20 mph is 25 feet.
\n" ); document.write( ".
\n" ); document.write( "For 60 mph:
\n" ); document.write( "\"D=%281%2F16%2960%5E2\"=\"%281%2F16%293600=225ft\"
\n" ); document.write( "ANSWER 2: The braking distance at 60 mph is 225 feet.
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\n" ); document.write( "If the distance is 25 feet, speed is 20 mph. (See ANSWER 1)
\n" ); document.write( "-OR-
\n" ); document.write( "\"D=%281%2F16%29x%5E2\"
\n" ); document.write( "\"16D=x%5E2\"
\n" ); document.write( "\"x=sqrt%2816D%29\"=\"4%28sqrt%28D%29%29\" Plug in value for D and solve.
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