document.write( "Question 82377: Find the slope of the line containing the given points:\r
\n" ); document.write( "\n" ); document.write( "(z + q,z) and (z - q,z)\r
\n" ); document.write( "\n" ); document.write( "note: i know the formula of slope, m, is Y - Y1/X - X1. This is what i was thinking, please let me know where i'm going wrong. i have the solutions manual, but its not making sense. i don't know if x and x1 are both equal to z, or if you have to somehow factor z +/- q,z in both problems to get the solution. the manual has the first step typed out as: z-z/2-q-(z+q), and then of course 0/2q. however, i don't understand how the first step to the solution was solved. thank you. Joanna
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Algebra.Com's Answer #59031 by 303795(602)\"\" \"About 
You can put this solution on YOUR website!
If the first point is labelled as (X,Y) and the second point is labelled as (X1,Y1)
\n" ); document.write( "Then for the first point X = z + q and Y = z
\n" ); document.write( "For the second point X1 = z - q and Y1 = z
\n" ); document.write( "\"m+=+%28Y+-+Y1%29%2F%28X+-+X1%29\"
\n" ); document.write( "Substitute the X, Y, X1 and Y1 values into the gradient equation.
\n" ); document.write( "\"m+=+%28z+-+z%29%2F%28%28z+%2B+q%29+-+%28z+-+q%29%29\" Take (z - q) changes the signs to (-z + q)
\n" ); document.write( "\"m+=+%280%29%2F%28z+%2B+q+-+z+%2B+q%29\"
\n" ); document.write( "\"m+=+%280%29%2F%282q%29\"
\n" ); document.write( "ie the slope is zero. The line is parallel to the x axis.
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