document.write( "Question 965808: A rectangular patio is 4yards longer than it is wide. The area is 448 square feet. What is the width in feet? \n" ); document.write( "
Algebra.Com's Answer #590295 by MathLover1(20850)\"\" \"About 
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if a rectangular patio is \"4yd\" longer than it is wide, then \"L=W%2B4yd\"
\n" ); document.write( "\"1yd=3ft\", so \"L=W%2B12ft\"
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\n" ); document.write( "if the area is \"A=448ft%5E2\", then\r
\n" ); document.write( "\n" ); document.write( "\"L%2AW=448ft%5E2\"....substitute \"L\"\r
\n" ); document.write( "\n" ); document.write( "\"%28W%2B12ft%29%2AW=448ft%5E2\"
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\n" ); document.write( "\"W%5E2%2B12ft%2AW=448ft%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"W%5E2%2B12ft%2AW-448ft%5E2=0\"...factor completely\r
\n" ); document.write( "\n" ); document.write( "\"W%5E2%2B28ft%2AW-16ft%2AW-448ft%5E2+=+0\"......group\r
\n" ); document.write( "\n" ); document.write( "\"%28W%5E2%2B28ft%2AW%29-%2816ft%2AW%2B448ft%5E2+%29=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"W%28W%2B28ft%29-16ft%28W%2B28ft%29=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28W-16ft%29%28W%2B28ft%29+=+0\"\r
\n" ); document.write( "\n" ); document.write( "solutions:\r
\n" ); document.write( "\n" ); document.write( "if
\n" ); document.write( "\"%28W-16ft%29+=+0\"=>\"W=16ft\"\r
\n" ); document.write( "\n" ); document.write( "if
\n" ); document.write( "\"%28W%2B28ft%29+=+0\"=>\"W=-28ft\"=>the width cannot be negative, so disregad this solution\r
\n" ); document.write( "\n" ); document.write( "so, the width in feet is \"W=16ft\"\r
\n" ); document.write( "\n" ); document.write( "and the length is \"L=16ft%2B12ft\"=>\"L=28ft\"\r
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