document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=965716>Question 965716</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a ball is thrown up with an initial velocity of 48ft per second. Its height s after t is given by the equation s = 48t-16ft^2. Find the maximum height attained by the ball and the time it takes for the ball to return to Earth </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #590252 by </B><A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><B>amarjeeth123(569)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=590252\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> s=48t-16t^2<BR>\n" );
document.write( "Velocity v=ds/dt=48-32t<BR>\n" );
document.write( "For maximum height v=0<BR>\n" );
document.write( "48-32t=0<BR>\n" );
document.write( "32t=48<BR>\n" );
document.write( "t=48/32=1.5 sec<BR>\n" );
document.write( "Maximum height s(max)=48(1.5)-16(1.5^2)=72-36=36 feet.<BR>\n" );
document.write( "Total time to come back to Earth=1.5(2)=3 sec </SPAN>\n" );
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