document.write( "Question 965693: Find three consecutive positive odd integers such that the product of the first and third is equal to 1 less than twice the second \n" ); document.write( "

Algebra.Com's Answer #590250 by amarjeeth123(569) $\"\"$ $\"About$

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Let the three consecutive odd integers be (x-2),x and (x+2) respectively.
\n" ); document.write( "We have (x-2)(x+2)=2x-1
\n" ); document.write( "x^2-4=2x-1
\n" ); document.write( "x^2-2x-3=0
\n" ); document.write( "x^2-3x+x-3=0
\n" ); document.write( "x(x-3)+1(x-3)=0
\n" ); document.write( "(x+1)(x-3)=0
\n" ); document.write( "x=3
\n" ); document.write( "The consecutive odd integers are 1,3 and 5 respectively. \n" ); document.write( "

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