document.write( "Question 965680: the base of a container is a square of side 30 cm. a stone is placed in the container. then water is poured into the container until it is 3/4 full. when the stone is removed, the water level drops to 5/8 of the height of the container. if the volume of the stone is 4500 cubed cm, find the height of the container. \n" ); document.write( "
Algebra.Com's Answer #590232 by josgarithmetic(39617)\"\" \"About 
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When the stone is removed, occupied tank volume changes from 3/4 full to 5/8 full;
\n" ); document.write( "when 4500 cm^3 is removed, the tank filled volume changes from 6/8 full to 5/8 full;\r
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\n" ); document.write( "\n" ); document.write( "When \"4500%2Acm%5E3\" is removed, the was a tank volume change of \"6%2F8-5%2F8=1%2F8\" of the tank's volume.\r
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\n" ); document.write( "\n" ); document.write( "The tank volume is proportional to its height or tallness.
\n" ); document.write( "\"30%2A30%2Ay=4500\", using y for the amount of vertical length along the tank for the stone.\r
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\n" ); document.write( "\n" ); document.write( "\"y=4500%2F900\"
\n" ); document.write( "\"y=45%2F9\"
\n" ); document.write( "\"y=5\", this is centimeters.\r
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\n" ); document.write( "\n" ); document.write( "That y=5 is \"%281%2F6%29\" of the tank's height.\r
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\n" ); document.write( "\n" ); document.write( "Finally, if h is the actual tank height\r
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\n" ); document.write( "\n" ); document.write( "\"highlight_green%28y%2Fh=1%2F6%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=h%2F6\"\r
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\n" ); document.write( "\n" ); document.write( "\"6%2Ay=h\"\r
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\n" ); document.write( "\n" ); document.write( "\"h=6%2Ay\"\r
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\n" ); document.write( "\n" ); document.write( "\"h=6%2A5\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28h=30%2Acentimeters%29\"
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