document.write( "Question 965599: The perimeter of a rectangle is 46in. It's length is two more than five times it width. Find its dimensions. \n" ); document.write( "
Algebra.Com's Answer #590198 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "W=width; L=length=5W+2; P=perimeter=46 in \n" ); document.write( "P=2(L+W) Substitute for L. \n" ); document.write( "46 in=2(5W+2+W) Divide each side by 2. \n" ); document.write( "23 in=6W+2 Subtract 2 from each side \n" ); document.write( "21 in=6W Divide each side by 6 \n" ); document.write( "3.5 in=W ANSWER 1: The width is 3.5 inches. \n" ); document.write( "L=5W+2=5(3.5in)+2=17.5in+2=19.5 in ANSWER 2: the length is 19.5 inches. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "P=2(L+W) \n" ); document.write( "46 in=2(19.5in+3.5in) \n" ); document.write( "46 in=2(23 in) \n" ); document.write( "46 in=46 in \n" ); document.write( " |