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document.write( "The perimeter of a rectangle is 52 cm. The length is 2 cm less than three times the width. Find the length and the width.
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Algebra.Com's Answer #590197 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! P=2L+2W \n" ); document.write( "L=3W-2 \n" ); document.write( "52=2(3W-2)+2W \n" ); document.write( "52=6W-4+2W \n" ); document.write( "52=8W-4 \n" ); document.write( "8W=52+4 \n" ); document.write( "8W=56 \n" ); document.write( "W=56/8 \n" ); document.write( "W=7 CM FOR THE WIDTH. \n" ); document.write( "L=3*7-2 \n" ); document.write( "L=21-2 \n" ); document.write( "L=19 CM FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "52=2*19+2*7 \n" ); document.write( "52=38+14 \n" ); document.write( "52=52 \n" ); document.write( " |