document.write( "Question 965605: \r
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\n" ); document.write( "\n" ); document.write( "The perimeter of a rectangle is 52 cm. The length is 2 cm less than three times the width. Find the length and the width.
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Algebra.Com's Answer #590197 by checkley77(12844)\"\" \"About 
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P=2L+2W
\n" ); document.write( "L=3W-2
\n" ); document.write( "52=2(3W-2)+2W
\n" ); document.write( "52=6W-4+2W
\n" ); document.write( "52=8W-4
\n" ); document.write( "8W=52+4
\n" ); document.write( "8W=56
\n" ); document.write( "W=56/8
\n" ); document.write( "W=7 CM FOR THE WIDTH.
\n" ); document.write( "L=3*7-2
\n" ); document.write( "L=21-2
\n" ); document.write( "L=19 CM FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "52=2*19+2*7
\n" ); document.write( "52=38+14
\n" ); document.write( "52=52
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