document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=965596>Question 965596</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two number is 98. If three times the smaller number is subtracted from the larger number, the result is 10. Find the two numbers.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #590194 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=590194\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "S=smaller number; L=larger number<BR>\n" );
document.write( "L+S=98<BR>\n" );
document.write( "L=98-S Use this to substitute for L<BR>\n" );
document.write( "L-3S=10 Substitute for L from above.<BR>\n" );
document.write( "98-S-3S=10 Subtract 98 from each side.<BR>\n" );
document.write( "-4S=-88 Divide each side by -4<BR>\n" );
document.write( "S=22 ANSWER 1: The smaller number is 22.<BR>\n" );
document.write( "L=98-S=98-22=76 ANSWER 2: The larger number is 76.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "L-3S=10<BR>\n" );
document.write( "76-3(22)=10<BR>\n" );
document.write( "76-66=10<BR>\n" );
document.write( "10=10<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );