document.write( "Question 965462: The width of a rectangle is 30% more than its length. The area of this rectangle is 2080 sq.cm. what is the area of a square whose side is half the length of rectangle? \n" ); document.write( "

Algebra.Com's Answer #590144 by macston(5194) $\"\"$ $\"About$

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\n" ); document.write( "L=Length; W=width=1.3L ( 30% more than length=130% L=1.3L); A=area=2080 sq cm
\n" ); document.write( " $\"LW=A\"$ Substitute for W.
\n" ); document.write( " $\"%28L%29%281.3L%29=2080cm%5E2\"$
\n" ); document.write( " $\"1.3L%5E2=2080cm%5E2\"$ Divide each side by 1.3.
\n" ); document.write( " $\"L%5E2=1600cm%5E2\"$
\n" ); document.write( " $\"L=40cm\"$
\n" ); document.write( "The length of the rectangle is 40 centimeters.
\n" ); document.write( ".
\n" ); document.write( "The side of the square is therefore 20 centimeters.
\n" ); document.write( "Area of square= $\"%28side%29%5E2=20cm%29%5E2\"$ = $\"400cm%5E2\"$
\n" ); document.write( "ANSWER: The area of the square is 400 square centimeters.\r
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