document.write( "Question 965449: Draw a pattern that can be used to create a cylinder with diameter equal to half the height.\r
\n" ); document.write( "\n" ); document.write( "here is a picture of the choices, please copy & paste thanks:).\r
\n" ); document.write( "\n" ); document.write( "http://prntscr.com/6x3uxn \r
\n" ); document.write( "\n" ); document.write( "thanks so much
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Algebra.Com's Answer #590143 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "The side of the cylinder will be formed by a rectangle:
\n" ); document.write( "\"%28Circumference%29\"\"x\"\"%28height%29\"
\n" ); document.write( ".
\n" ); document.write( "\"Circumference=%28pi%29%28diameter%29=2%28pi%29%28radius%29\"
\n" ); document.write( "\"Height=%282%29%28diameter%29\"=\"4%28radius%29\"
\n" ); document.write( ".
\n" ); document.write( "So the rectangle will be:
\n" ); document.write( "\"2%28pi%29r\"\"x\"\"4r\"
\n" ); document.write( ".
\n" ); document.write( "The correct answer is D.
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