document.write( "Question 965388: Solve on the interval from 0 to pi:2cos^2 x-3 sin x-3=0 \n" ); document.write( "

Algebra.Com's Answer #590142 by lwsshak3(11628) $\"\"$ $\"About$

You can put this solution on YOUR website!
Solve on the interval from 0 to pi:2cos^2 x-3 sin x-3=0
\n" ); document.write( " $\"2cos%5E2%28x%29-3sinx-3=0\"$
\n" ); document.write( " $\"2%281-sin%5E2%28x%29-3sinx-3=0\"$
\n" ); document.write( " $\"2-2sin%5E2%28x%29-3sinx-3=0\"$
\n" ); document.write( " $\"-2sin%5E2%28x%29-3sinx-1=0\"$
\n" ); document.write( " $\"2sin%5E2%28x%29%2B3sinx%2B1=0\"$
\n" ); document.write( "(2sinx+1)(sinx+1)=0
\n" ); document.write( "sinx=-1/2
\n" ); document.write( "no solution, not in domain
\n" ); document.write( "or
\n" ); document.write( "sinx=-1
\n" ); document.write( "no solution, not in domain \n" ); document.write( "

\n" );