document.write( "Question 965436: Find two integers whose product is 105 such that one of the integers is one more than twice the other integer. \n" ); document.write( "
Algebra.Com's Answer #590117 by macston(5194)\"\" \"About 
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\n" ); document.write( "x and y are the integers
\n" ); document.write( "x=2y+1
\n" ); document.write( "xy=105 Substitute for x
\n" ); document.write( "(2y+1)(y)=105 Subtract 105 from each side
\n" ); document.write( "2y^2+y-105=0\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ay%5E2%2Bby%2Bc=0\" (in our case \"2y%5E2%2B1y%2B-105+=+0\") has the following solutons:
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\n" ); document.write( " \"y%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%281%29%5E2-4%2A2%2A-105=841\".
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\n" ); document.write( " Discriminant d=841 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-1%2B-sqrt%28+841+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"y%5B1%5D+=+%28-%281%29%2Bsqrt%28+841+%29%29%2F2%5C2+=+7\"
\n" ); document.write( " \"y%5B2%5D+=+%28-%281%29-sqrt%28+841+%29%29%2F2%5C2+=+-7.5\"
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\n" ); document.write( " Quadratic expression \"2y%5E2%2B1y%2B-105\" can be factored:
\n" ); document.write( " \"2y%5E2%2B1y%2B-105+=+2%28y-7%29%2A%28y--7.5%29\"
\n" ); document.write( " Again, the answer is: 7, -7.5.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+2%2Ax%5E2%2B1%2Ax%2B-105+%29\"

\n" ); document.write( "\n" ); document.write( "y=7 ANSWER 1: One of the integers is 7
\n" ); document.write( "x=2y+1=2(7)+1=14+1=15 ANSWER 2: The other integer is 15\r
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