document.write( "Question 965404: Write an equation in slope-intercept form of a linear function f whose graph satisfies the given conditions.\r
\n" ); document.write( "\n" ); document.write( "The graph of f passes through (-6, 4) and is perpendicular to the line that has an x-intercept of 2 and a y–intercept of -4.\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #590108 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "slope-intercept form: \"y=mx%2Bb\" where \"m\" is a slope and \"b\" is y-intercept\r
\n" ); document.write( "\n" ); document.write( "given:
\n" ); document.write( "the graph of f passes through (\"-6\",\"+4\")
\n" ); document.write( " and
\n" ); document.write( "is perpendicular to the line that has an x-intercept of \"2\" and a y–intercept of \"-4\" \r
\n" ); document.write( "\n" ); document.write( "\"y=mx%2Bb\" if (\"-6\",\"+4\") on a line, then we have\r
\n" ); document.write( "\n" ); document.write( "\"4=-6m%2Bb\"........eq.1\r
\n" ); document.write( "\n" ); document.write( "if line is perpendicular to the line that has an x-intercept of \"2\" and a y–intercept of \"-4\" , then our line has a slope negative reciprocal to the slope of the line that has an x-intercept of \"2\" and a y–intercept of \"-4\"\r
\n" ); document.write( "\n" ); document.write( "first find the equation of the line that has an x-intercept of \"2\" and a y–intercept of \"-4\"\r
\n" ); document.write( "\n" ); document.write( "if the line that has an x-intercept of \"2\", then the point (\"2\",\"0\") is on a line\r
\n" ); document.write( "\n" ); document.write( "so, we have\r
\n" ); document.write( "\n" ); document.write( "\"0=m%5Bp%5D%2A2%2Bb\" \r
\n" ); document.write( "\n" ); document.write( "\"0=2m%5Bp%5D%2Bb\"........... eq.2 \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "if the line that has an y-intercept of \"-4\", then the point (\"0\",\"-4\") is on a line\r
\n" ); document.write( "\n" ); document.write( "so, we have\r
\n" ); document.write( "\n" ); document.write( "\"-4=m%5Bp%5D%2A0%2Bb\" \r
\n" ); document.write( "\n" ); document.write( "\"-4=0%2Bb\"\r
\n" ); document.write( "\n" ); document.write( "\"b=-4\".......substitute in eq.2 and find \"m%5Bp%5D\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"0=2m%5Bp%5D-4\"........... eq.2 \r
\n" ); document.write( "\n" ); document.write( "\"2m%5Bp%5D=4\"\r
\n" ); document.write( "\n" ); document.write( "\"m%5Bp%5D=2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "so, the equation of the line is perpendicular to the line that has an x-intercept of \"2\" and a y–intercept of \"-4\" is\r
\n" ); document.write( "\n" ); document.write( "\"y=2x-4\" \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "since the slope is \"m%5Bp%5D=2\", our line will have the slope \"m=-1%2F2\" which is is the negative reciprocal of the \"m%5Bp%5D=2\"\r
\n" ); document.write( "\n" ); document.write( "so far we have \"y=-%281%2F2%29x%2Bb\" and we need to find \"b\"
\n" ); document.write( "\"y=2x-4\" \r
\n" ); document.write( "\n" ); document.write( "use \"4=-6m%2Bb\"........eq.1, substitute \"m=-1%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"4=-6%28-%281%2F2%29%29%2Bb\"\r
\n" ); document.write( "\n" ); document.write( "\"4=cross%286%29%281%2Fcross%282%29%29%2Bb\"\r
\n" ); document.write( "\n" ); document.write( "\"4=3%2Bb\"\r
\n" ); document.write( "\n" ); document.write( "\"b=4-3\"\r
\n" ); document.write( "\n" ); document.write( "\"b=1\"\r
\n" ); document.write( "\n" ); document.write( "so, the equation of a line we are looking for is: \"y=-%281%2F2%29x%2B1\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );