document.write( "Question 82346: The length of a rectangle is 1 cm more than 4 times its width. If the area of the rectangle is 72 cm^2, find the dimensions of the rectangle to the nearest thousandth.\r
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Algebra.Com's Answer #59010 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let W=width of rectangle \n" ); document.write( "Then length=4W+1\r \n" ); document.write( "\n" ); document.write( "Area(A) of rectangle=Length*Width=W*(4W+1)\r \n" ); document.write( "\n" ); document.write( "Now we are told that: \n" ); document.write( " W*(4W+1)=72 get rid of parens\r \n" ); document.write( "\n" ); document.write( "4W^2+W=72 subtract 72 from both sides\r \n" ); document.write( "\n" ); document.write( "4W^2+W-72=72-72 or\r \n" ); document.write( "\n" ); document.write( "4W^2+W-72=0 quadratic in standard form. We'll use the quadratic formula:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Discount negative value for W. Lengths are positive.\r \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "A=L*W=(4.120)(17.480)=72 cm^2\r \n" ); document.write( "\n" ); document.write( "~72 cm^2=72 cm^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |