document.write( "Question 82346: The length of a rectangle is 1 cm more than 4 times its width. If the area of the rectangle is 72 cm^2, find the dimensions of the rectangle to the nearest thousandth.\r
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Algebra.Com's Answer #59010 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Let W=width of rectangle
\n" ); document.write( "Then length=4W+1\r
\n" ); document.write( "\n" ); document.write( "Area(A) of rectangle=Length*Width=W*(4W+1)\r
\n" ); document.write( "\n" ); document.write( "Now we are told that:
\n" ); document.write( " W*(4W+1)=72 get rid of parens\r
\n" ); document.write( "\n" ); document.write( "4W^2+W=72 subtract 72 from both sides\r
\n" ); document.write( "\n" ); document.write( "4W^2+W-72=72-72 or\r
\n" ); document.write( "\n" ); document.write( "4W^2+W-72=0 quadratic in standard form. We'll use the quadratic formula:\r
\n" ); document.write( "\n" ); document.write( "\"W+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\" \r
\n" ); document.write( "\n" ); document.write( "\"W+=+%28-1+%2B-+sqrt%28+1%5E2-4%2A4%2A%28-72%29+%29%29%2F%282%2A4%29+\" \r
\n" ); document.write( "\n" ); document.write( "\"W+=+%28-1+%2B-+sqrt%281153%29%29%2F%288%29+\" \r
\n" ); document.write( "\n" ); document.write( "\"W+=+%28-1+%2Bsqrt+%281153%29%29%2F%288%29+\" \r
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\n" ); document.write( "\n" ); document.write( "\"W+=+4.120\" cm ----------------------width of rectangle\r
\n" ); document.write( "\n" ); document.write( "\"4W%2B1=4%284.120%29%2B1=17.480\" cm---------------------length of rectangle\r
\n" ); document.write( "\n" ); document.write( "Discount negative value for W. Lengths are positive.\r
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\n" ); document.write( "\n" ); document.write( "A=L*W=(4.120)(17.480)=72 cm^2\r
\n" ); document.write( "\n" ); document.write( "~72 cm^2=72 cm^2\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor\r
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