document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=82309>Question 82309</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two cars traveled in opposite directions from the same starting point. The rate of one car was 15km/h faster than the rate of the other car. After 2hr, the cars were 240 kn apart. find each car's rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #59009 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=59009\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> distance(d)=rate(r) times time(t) or d=rt; r=d/t and t=d/r\r<BR>\n" );
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document.write( "Let r=rate of first car<BR>\n" );
document.write( "Then r+15=rate of other car\r<BR>\n" );
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document.write( "Distance first car travels in 2 hours=rt=2r<BR>\n" );
document.write( "Distance other car travels in 2 hours=rt=2(r+15)\r<BR>\n" );
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document.write( "Now we are told that the distance first car travels plus the distance second car travels equals 240 km.  So:\r<BR>\n" );
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document.write( "2r+2(r+15)=240  get rid of parens\r<BR>\n" );
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document.write( "2r+2r+30=240  subtract 30 from both sides\r<BR>\n" );
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document.write( "2r+2r+30-30=240-30  collect like terms\r<BR>\n" );
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document.write( "4r=210  divide both sides by 4<BR>\n" );
document.write( "r=52.5 km/hr----------------------------rate of first car\r<BR>\n" );
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document.write( "r+15=52.5+15=67.5 km/hr---------------------rate of other car\r<BR>\n" );
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document.write( "CK\r<BR>\n" );
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document.write( "2(52.5)+2(67.5)=240<BR>\n" );
document.write( "105+135=240<BR>\n" );
document.write( "240=240\r<BR>\n" );
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document.write( "Another way to look at this problem is to note that the two cars are separating at the rate of (r+r+15) km/hr . So in 2 hrs, they will have separated 2(r+r+15) km or 2r+2r+30 and that equals 240 km---same eq as before.\r<BR>\n" );
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document.write( "Hope this helps--------------------ptaylor<BR>\n" );
document.write( " </SPAN>\n" );
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