document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=965345>Question 965345</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If angle a and angle b are supplementary angles and angle A is four times as large as angle b than what would there measurements be> </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #590060 by </B><A HREF=/tutors/aboutme.mpl?userid=rm29924><B>rm29924(97)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rm29924><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rm29924><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=590060\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> supplementary angles add up to 180 degrees<BR>\n" );
document.write( "so we know a + b = 180<BR>\n" );
document.write( "a is four times as large as b<BR>\n" );
document.write( "so a = 4b<BR>\n" );
document.write( "substitute 4b for a into a + b = 180<BR>\n" );
document.write( "4b + b =180<BR>\n" );
document.write( "combine like terms<BR>\n" );
document.write( "5b = 180<BR>\n" );
document.write( "divide both sides by 5 to get the variable b by itself<BR>\n" );
document.write( "b = 36<BR>\n" );
document.write( "plug 36 back into the original equation to figure out what a is<BR>\n" );
document.write( "a + 36 = 180<BR>\n" );
document.write( "subtract 36 from both sides<BR>\n" );
document.write( "a = 144\r<BR>\n" );
document.write( "\n" );
document.write( "answer angle a is 144 degrees and angle b is 36 degrees<BR>\n" );
document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );