document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=965233>Question 965233</A>: <I><SPAN STYLE=\"word-break: break-all;\"> tire radius of 21 in profile 12in what is surface area 20 % making contact </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #589982 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=589982\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> tire radius of 21 in profile 12in what is surface area 20 % making contact<BR>\n" );
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document.write( "It's a cylinder<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=SA+=+pi%2Ar%5E2%2Ah+=+pi%2A441%2A12+=+16625 ALIGN=MIDDLE  ALT=\"SA+=+pi%2Ar%5E2%2Ah+=+pi%2A441%2A12+=+16625\"   DISABLED_style= \"max-width:90%; height:auto;\" > sq inches<BR>\n" );
document.write( "20% of that = 3325 sq inches<BR>\n" );
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document.write( "It's not likely that a tire on any vehicle has 20% of its surface in contact with the ground.<BR>\n" );
document.write( "If you meant 20 degrees,<BR>\n" );
document.write( "16625*20/360 = 924 sq inches </SPAN>\n" );
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