document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=965160>Question 965160</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Having trouble proving the following half angle identity:  csc^2 x/2 = 2 sec X/ sec -1. If you could please explain the steps. I started working on the left side, used the sin a/2 identity formula and flipped it for CSC. \r<BR>\n" );
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document.write( "Csc^2x/2 = 2/1-cos X. This is where I got stuck. Not sure if I'm on the right track. \r<BR>\n" );
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document.write( "Thank you in advance for your help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #589904 by </B><A HREF=/tutors/aboutme.mpl?userid=t0hierry><B>t0hierry(194)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=t0hierry><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=t0hierry><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=589904\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> csc^2 x/2 = 1/sin^2(x/2) = 2/(1-cosx) <BR>\n" );
document.write( "lol I'm stuck too.  </SPAN>\n" );
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