document.write( "Question 965140: The lateral area of a pyramid with a square base is 2400in^2. Its base edges are 48in long. Find the height of the pyramid. \n" ); document.write( "
Algebra.Com's Answer #589898 by macston(5194)\"\" \"About 
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lateral area/4=area of one side =1/2(base edge)(slant height)
\n" ); document.write( "\"2400in%5E2%2F4=%281%2F2%29bs\"
\n" ); document.write( "\"600in%5E2=%281%2F2%29%2848in%29%28s%29\"
\n" ); document.write( "\"600in%5E2=%2824in%29s\"
\n" ); document.write( "\"25in=s\" The slant height is 25 inches.
\n" ); document.write( "The height and 1/2 the base length form a right triangle with the slant height as hypotenuse, so:
\n" ); document.write( "\"s%5E2=%28b%2F2%29%5E2%2Bh%5E2\" where h is the height
\n" ); document.write( "\"%2825in%29%5E2=%2824in%29%5E2%2Bh%5E2\"
\n" ); document.write( "\"%2825in%29%5E2-%2824in%29%5E2=h%5E2\"
\n" ); document.write( "\"sqrt%28%28625in%5E2%29-%28576in%5E2%29%29=h\"
\n" ); document.write( "\"sqrt%2849in%5E2%29=h\"
\n" ); document.write( "\"7in=h\" ANSWER: The height of the pyramid is 7 inches.
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