document.write( "Question 965068: Greg drove at a constant speed in a rainstorm for 294 miles. He took a break, and the rain stopped. He then drove 156 miles at a speed that was 3 mph faster than his pervious speed. If he drove for 9 hours, find the cars speed for each part of the trip. \n" ); document.write( "
Algebra.Com's Answer #589875 by MathTherapy(10552)\"\" \"About 
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Greg drove at a constant speed in a rainstorm for 294 miles. He took a break, and the rain stopped. He then drove 156 miles at a speed that was 3 mph faster than his pervious speed. If he drove for 9 hours, find the cars speed for each part of the trip.
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Let speed during 1st leg of trip, be S
\n" ); document.write( "Then speed during 2nd leg = S + 3
\n" ); document.write( "Time taken to complete 1st leg: \"294%2FS\"
\n" ); document.write( "Time taken to complete 2nd leg: \"156%2F%28S+%2B+3%29\"
\n" ); document.write( "We then get: \"294%2FS+%2B+156%2F%28S+%2B+3%29+=+9\"
\n" ); document.write( "294(S + 3) + 156S = 9(S)(S + 3) ------- Multiplying by LCD, S(S + 3)
\n" ); document.write( "\"294S+%2B+882+%2B+156S+=+9S%5E2+%2B+27S\"
\n" ); document.write( "\"450S+%2B+882+=+9S%5E2+%2B+27S\"
\n" ); document.write( "\"9S%5E2+%2B+27S+-+450S+-+882+=+0\"
\n" ); document.write( "\"9S%5E2+-+423S+-+882+=+0\"
\n" ); document.write( "\"9%28S%5E2+-+47S+-+98%29+=+9%280%29\"
\n" ); document.write( "\"S%5E2+-+47S+-+98+=+0\"
\n" ); document.write( "(S - 49)(S + 2) = 0
\n" ); document.write( "S, or speed on 1st leg = \"highlight_green%2849%29\" mph OR S = - 2 (ignore)
\n" ); document.write( "Speed on 2nd leg: 49 + 3, or \"highlight_green%2852%29\" mph \n" ); document.write( "
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