document.write( "Question 965093: In still water, Jacob's sailboat cruises at 16.5 km/h. On the river near their cottage, the boat travels faster downstream than upstream, because of the current. The boat takes 5 hours for a trip upstream but only 2 hours to do the same distance on the return downstream. Determine the speed of the current by jacobs cottage \n" ); document.write( "
Algebra.Com's Answer #589852 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! r, boat speed when no river current \n" ); document.write( "c, speed of river current \n" ); document.write( "u, time upstream \n" ); document.write( "v, time downstream \n" ); document.write( "d, the one-way trip distance\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "RT=D for rate time distance relationship\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "____________________rate____________time__________distance \n" ); document.write( "UPSTREAM____________r-c_____________u____________(r-c)*u=d \n" ); document.write( "DOWNSTREAM__________r+c_____________v____________(r+c)*v=d\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve for c. \n" ); document.write( " |