document.write( "Question 964991: I need help finding the parabola of g(x)=1/2(x-2)^2-4. I know the vertex is (-2,4) but the graph shows (2-2sqrt2,0) and 2+2sqrt2,0) also (0,-2). \n" ); document.write( "
Algebra.Com's Answer #589810 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "I need help finding the parabola of g(x)=1/2(x-2)^2-4. I know the vertex is (-2,4) but the graph shows (2-2sqrt2,0) and 2+2sqrt2,0) also (0,-2).
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y is 0 on the x-axis, so (\"2+-+2+%2A+sqrt%282%29\"\"%22%2C%22\"\"0\") and (\"2+%2B+2+%2A+sqrt%282%29\"\"%22%2C%22\"\"0\") are the x-intercepts
\n" ); document.write( "x is 0 on the y-axis, so (\"0\"\"%22%27%22\"\"-+2\") is the y-intercept
\n" ); document.write( "You've already determined the coordinates of the vertex, so you have what's needed to form the equation of the parabola \n" ); document.write( "
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