document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=964970>Question 964970</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if a circle and a square have the same area of any number, what would be the circles perimeter?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #589806 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=589806\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the area of the circle and the square have area 25, then<BR>\n" );
document.write( "Area(A) of circle = pi*r^2 where r is the radius,<BR>\n" );
document.write( "25 = pi*r^2<BR>\n" );
document.write( "r^2 = 25 / pi <BR>\n" );
document.write( "r = sqrt(25 / pi) = 5*sqrt(1/pi)<BR>\n" );
document.write( "note the diameter(d) of a circle = 2*r<BR>\n" );
document.write( "d = 2*5*sqrt(1/pi) = 10*sqrt(1/pi)<BR>\n" );
document.write( "circumference(c) of  circle = pi*d, where d is the diameter<BR>\n" );
document.write( "c = pi * 10 * sqrt(1/pi)<BR>\n" );
document.write( "note using pi = 3.14<BR>\n" );
document.write( "c = 3.14 * 10 * sqrt(1/3.14) = 17.720045147 approx 17.72<BR>\n" );
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