document.write( "Question 82339: A garden area is 30 ft. long and 20 ft. wide. A path of uniform width is set around the edge. If the remaining garden area is 400 ft^2, what is the width of the path. \n" ); document.write( "
Algebra.Com's Answer #58980 by checkley75(3666)\"\" \"About 
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30*20=600 THE ORIGINAL AREA
\n" ); document.write( "(30-2X)(20-2X)=400 THE REMAINING GARDEN
\n" ); document.write( "600-40X-60X+4X^2=400
\n" ); document.write( "4X^2-100X+200=0
\n" ); document.write( "X^2-25X+50=0
\n" ); document.write( "USING THE QUADRATIC EQUATION WE GET:
\n" ); document.write( "X=(25+-SQRT[-25*-25-4*1*50])/2*1
\n" ); document.write( "X=(25+-SQRT[625-200])/2
\n" ); document.write( "X=(25+-SQRT425)/2
\n" ); document.write( "X=(25+-20.6)/2
\n" ); document.write( "X=(25+20.6)/2
\n" ); document.write( "X=45.6/2
\n" ); document.write( "X=22.8 NON ANSWER.
\n" ); document.write( "X=(25-20.6)/2
\n" ); document.write( "X=4.4/2
\n" ); document.write( "X=2.2 ANSWER FOR THE WIDTH OF THE PATH.
\n" ); document.write( "PROOF
\n" ); document.write( "(30-4.4)*(20-4.4)=400
\n" ); document.write( "25.6*15.6=400
\n" ); document.write( "400=400
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