document.write( "Question 964995: The length of a rectangle is three feet longer than six times its width.
\n" ); document.write( "If the area of the rectangle is 165 square feet, what is the width of the
\n" ); document.write( "rectangle? \n" ); document.write( "

Algebra.Com's Answer #589763 by macston(5194) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "W=width; L=length=6W+3ft; A=area=165ft^2
\n" ); document.write( " $\"LW=A\"$ Substitute for L
\n" ); document.write( " $\"%286W%2B3ft%29%28W%29=165ft%5E2\"$
\n" ); document.write( " $\"6W%5E2%2B3Wft=165ft%5E2\"$ Subtract 165ft^2 from each side.
\n" ); document.write( " $\"6W%5E2%2B3Wft-165ft%5E2=0\"$ Divide by 3
\n" ); document.write( " $\"2W%5E2%2BW-55=0\"$
\n" ); document.write( " $\"%282W%2B11%29%28W-5%29=0\"$
\n" ); document.write( " $\"2W%2B11=0\"$ $\"or\"$ $\"W-5=0\"$
\n" ); document.write( " $\"2W=-11\"$ $\"or\"$ $\"W=5\"$
\n" ); document.write( " $\"W=-5.5\"$ $\"or\"$ $\"W=5\"$
\n" ); document.write( "ANSWER: The width is 5 feet.
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\n" ); document.write( "CHECK:
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\n" ); document.write( " $\"L=6W%2B3ft\"$ = $\"6%285ft%29%2B3ft=39ft%2B3ft\"$ = $\"33ft\"$ Length is 33 feet.
\n" ); document.write( " $\"LW=A\"$
\n" ); document.write( " $\"%2833ft%29%285ft%29=165ft%5E2\"$
\n" ); document.write( " $\"165ft%5E2=165ft%5E2\"$ \n" ); document.write( "

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