document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=964834>Question 964834</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a perimeter is 130 feet and the length is 5 feet longer than the width,  then what is the length and width? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #589693 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=589693\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "W=width; L=length=W+5 feet; P=perimeter=130 feet<BR>\n" );
document.write( "P=2(L+W) Substitute for L<BR>\n" );
document.write( "130 feet=2(W+5 feet+W) Divide each side by 2.<BR>\n" );
document.write( "65 feet=2W+5 feet Subtract 5 feet from each side.<BR>\n" );
document.write( "60 feet=2W Divide each side by 2.<BR>\n" );
document.write( "30 feet=W ANSWER 1: The width is 30 feet<BR>\n" );
document.write( "L=W+5 feet=30 feet+5 feet=35 feet ANSWER 2: The length is 35 feet.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( ".<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "130 feet=2(35 feet+30 feet)<BR>\n" );
document.write( "130 feet=2(65 feet)<BR>\n" );
document.write( "130 feet=130 feet </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );