document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=964854>Question 964854</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boat moves 9 kilometers upstream in the same amount of time it moves 15 kilometers downstream. If the rate of the current is 8 kilometers per hour, find the rate of the boat in still water. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #589689 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=589689\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> r=rate in still water<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=15km%2F%28r%2B8km%2Fhr%29=9km%2F%28r-8km%2Fhr%29 ALIGN=MIDDLE  ALT=\"15km%2F%28r%2B8km%2Fhr%29=9km%2F%28r-8km%2Fhr%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Cross multiply.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=15km%28r-8km%2Fhr%29=9km%28r%2B8km%2Fhr%29%7D%7D%0D%0A%7B%7B%7B15rkm-120km%5E2%2Fhr=9rkm%2B72km%5E2%2Fhr ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract 9rkm from each side.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6rkm-120km%5E2%2Fhr=72km%5E2%2Fhr ALIGN=MIDDLE  ALT=\"6rkm-120km%5E2%2Fhr=72km%5E2%2Fhr\"   DISABLED_style= \"max-width:90%; height:auto;\" > Add 120km^2/hr to each side.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6rkm=192km%5E2%2Fhr ALIGN=MIDDLE  ALT=\"6rkm=192km%5E2%2Fhr\"   DISABLED_style= \"max-width:90%; height:auto;\" > Divide each side by 6km.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r=32km%2Fhr ALIGN=MIDDLE  ALT=\"r=32km%2Fhr\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "ANSWER: The rate of the boat in still water is 32 km/hr.<BR>\n" );
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document.write( "CHECK:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=15km%2F%2832km%2Fhr%2B8km%2Fhr%29=9km%2F%2832km%2Fhr-8km%2Fhr%29 ALIGN=MIDDLE  ALT=\"15km%2F%2832km%2Fhr%2B8km%2Fhr%29=9km%2F%2832km%2Fhr-8km%2Fhr%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=15km%2F%2840km%2Fhr%29=9km%2F%2824km%2Fhr%29 ALIGN=MIDDLE  ALT=\"15km%2F%2840km%2Fhr%29=9km%2F%2824km%2Fhr%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.375hr=0.375hr ALIGN=MIDDLE  ALT=\"0.375hr=0.375hr\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( " </SPAN>\n" );
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