document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=964850>Question 964850</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 7 meters more than twice the width the area is 60 square meters find the length and width </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #589670 by </B><A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><B>amarjeeth123(569)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=589670\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the width be x.<BR>\n" );
document.write( "Then the length is (2x+7).<BR>\n" );
document.write( "Area=length*width<BR>\n" );
document.write( "x(2x+7)=60<BR>\n" );
document.write( "2x^2+7x-60=0<BR>\n" );
document.write( "2x^2-8x+15x-60=0<BR>\n" );
document.write( "2x(x-4)+15(x-4)=0<BR>\n" );
document.write( "(2x+15)(x-4)=0<BR>\n" );
document.write( "x=4 is the only feasible solution as x cannot be negative.<BR>\n" );
document.write( "The width is 4 metres.<BR>\n" );
document.write( "The length is 15 metres. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );