document.write( "Question 82318: the tens digit of a two digit is three more than the units digit if the digits are revered the new number is 54 less than the original number. find the original number \n" ); document.write( "
Algebra.Com's Answer #58967 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! x=y+3 \n" ); document.write( "10x+y=10y+x+54 now substitute (y+3) for x & solve for y. \n" ); document.write( "10(y+3)+y=10y+(y+3)+54 \n" ); document.write( "10y+30+y=10y+y+3+54 \n" ); document.write( "11y-11y=57-30 \n" ); document.write( "0=27 this would indicate that every set of numbers results in a difference of not 54 but 27. Thus: \n" ); document.write( "96 \n" ); document.write( "-69 \n" ); document.write( "--- \n" ); document.write( "27 \r \n" ); document.write( "\n" ); document.write( "85 \n" ); document.write( "-58 \n" ); document.write( "---- \n" ); document.write( "27\r \n" ); document.write( "\n" ); document.write( "74 \n" ); document.write( "-47 \n" ); document.write( "--------- \n" ); document.write( "27 \n" ); document.write( "&\r \n" ); document.write( "\n" ); document.write( "30 \n" ); document.write( "-03 \n" ); document.write( "--------- \n" ); document.write( "27 \n" ); document.write( " \n" ); document.write( " |