document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=964843>Question 964843</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If perimeter of pool is 576 ft. The width is 1/3 its length, what are the dimensions?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #589663 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=589663\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "L=length; W=width=(1/3)L; P=perimeter=576ft<BR>\n" );
document.write( "P=2(L+W) Substitute for W.<BR>\n" );
document.write( "576ft=2(L+(1/3)L) Divide each side by 2.<BR>\n" );
document.write( "288ft=(4/3)L<BR>\n" );
document.write( "288ft=(4/3)L Multiply each side by 3/4.<BR>\n" );
document.write( "216ft=L ANSWER 1: The length is 216 feet.<BR>\n" );
document.write( "W=(1/3)L=(1/3)216ft=72 ft  ANSWER 2: The width is 72 feet.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "576ft=2(216ft+72ft)<BR>\n" );
document.write( "576ft=2(288ft)<BR>\n" );
document.write( "576ft=576ft\r<BR>\n" );
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