document.write( "Question 963525: What is the cost to build a sidewalk 3' wide and 4\" deep around the inside perimeter of a lot 100' x 150', if the price of concrete is $24 a cubic yard?\r
\n" ); document.write( "\n" ); document.write( "please email to lora_dubois@verizon.net \r
\n" ); document.write( "\n" ); document.write( "Thanks!!
\n" ); document.write( "

Algebra.Com's Answer #589619 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
The outside dimension of the walk is (100'+6') x (150'+6'),
\n" ); document.write( "so the area of walk and lot is (106')(156')=16536ft^2
\n" ); document.write( "The area of the lot is (100')(150')=15000ft^2
\n" ); document.write( "So area of walk=(area of lot+walk)-(area of lot)=16536ft^2-15000ft^2=1536ft^2
\n" ); document.write( "There are 9ft^2 per yd^2:
\n" ); document.write( "(1536ft^2)(1yd^2/9ft^2)=170.67yd^2
\n" ); document.write( "The area of the walk is 170.67 square yards.
\n" ); document.write( "The depth of the walk is (1/9)yard so the volume is:
\n" ); document.write( "(170.67yds^2)(1/9 yd)=18.96yd^3
\n" ); document.write( "Cost of concrete=(18.96yd^3)($24/yd^3)=$455.04
\n" ); document.write( "ANSWER: The cost of the concrete would be $455.04.
\n" ); document.write( "
\n" ); document.write( "
\n" );