document.write( "Question 964689: It takes John 3 times as long as it takes Jessica to mow a lawn. If it took them both 11 hours to mow the lawn, how long would it take John to mow the lawn alone?
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Algebra.Com's Answer #589514 by stanbon(75887)\"\" \"About 
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It takes John 3 times as long as it takes Jessica to mow a lawn. If it took them both 11 hours to mow the lawn, how long would it take John to mow the lawn alone?
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\n" ); document.write( "John's rate:: 1/(3x) job/hr
\n" ); document.write( "Jessica's rate: 1/x job/hr
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\n" ); document.write( "Together rate:: 1/11 job/hr
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\n" ); document.write( "Equation::
\n" ); document.write( "rate + rate = together rate
\n" ); document.write( "1/(3x) + 1/x = 1/11
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\n" ); document.write( "11x + 33x = x*3x
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\n" ); document.write( "3x^2 - 44x = 0
\n" ); document.write( "x(3x-44) = 0
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\n" ); document.write( "Non-zero solution::
\n" ); document.write( "x = 44/3
\n" ); document.write( "Ans: John's time to do the job alone = 3x = 3(44/3) = 44 hours
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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