document.write( "Question 11367: I cannot figure out how to start this equation\r
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document.write( " 3(x+4 -1) =15 The (x+4-1)is divided by 2
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Algebra.Com's Answer #5895 by elima(1433)![]() ![]() ![]() You can put this solution on YOUR website! 3(x+4 -1) =15 The (x+4-1)is divided by 2 \n" ); document.write( " 2\r \n" ); document.write( "\n" ); document.write( "3(x+3)=15 \n" ); document.write( " 2\r \n" ); document.write( "\n" ); document.write( "Divide 3 from both sides;\r \n" ); document.write( "\n" ); document.write( "x+3 = 15/3 \n" ); document.write( " 2\r \n" ); document.write( "\n" ); document.write( "multiply 2 to both sides;\r \n" ); document.write( "\n" ); document.write( "x+3 = 5(2)\r \n" ); document.write( "\n" ); document.write( "subtract 3 from both sides;\r \n" ); document.write( "\n" ); document.write( "x = 10-3 \n" ); document.write( "x=7\r \n" ); document.write( "\n" ); document.write( "check: \n" ); document.write( "3(7+4-1) = 15 \n" ); document.write( " 2\r \n" ); document.write( "\n" ); document.write( "3(10) = 15 \n" ); document.write( " 2\r \n" ); document.write( "\n" ); document.write( "30/2 = 15\r \n" ); document.write( "\n" ); document.write( "15=15 \n" ); document.write( " |