document.write( "Question 964570: Hi There! Can You Please Help Me Solve This?? I Just Don't Know How To Take The First Step...\r
\n" ); document.write( "\n" ); document.write( "Solve each equation over the complex numbers:\r
\n" ); document.write( "\n" ); document.write( "x^3+5x^2+4x+20=0\r
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Algebra.Com's Answer #589426 by josgarithmetic(39616)\"\" \"About 
You can put this solution on YOUR website!
Rational Roots Theorem and synthetic division. The roots to check would be -1, -2, -4,- 5, -10, maybe -20.\r
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\n" ); document.write( "\n" ); document.write( "You asked for a first step. Take as example 5; is \"x%2B5\" one of the binomial factors of the cubic polynomial? Check the root -5 using synthetic division.\r
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\n" ); document.write( "\n" ); document.write( "__________-5_______|_________1______5_______4_______20
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\n" ); document.write( "__________________|_______________-5________0______-20
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\n" ); document.write( "____________________________1______0______4_________0\r
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\n" ); document.write( "\n" ); document.write( "Remainder is 0, so this means -5 is a root, or equivalently, (x+5) is one of the binomial factors of the polynomial given.\r
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\n" ); document.write( "\n" ); document.write( "The quotient from the synthetic division shows the other factor is \"x%5E2%2B4\". This will have two complex roots.
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