document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=964544>Question 964544</A>: <I><SPAN STYLE=\"word-break: break-all;\"> for f(x)=-3x+7, find the value of x that leads to the given value of f(x).\r<BR>\n" );
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document.write( "f(x)= 5/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #589397 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=589397\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> for f(x)=-3x+7, find the value of x that leads to the given value of f(x). <BR>\n" );
document.write( "f(x)= 5/2<BR>\n" );
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document.write( "Solve:: -3x+7 = 5/2<BR>\n" );
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document.write( "-6x + 14 = 5<BR>\n" );
document.write( "-6x = -9<BR>\n" );
document.write( "x = 3/2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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