document.write( "Question 964529: Jenny and Penny can eat a whole gallon of ice cream together in 2 hours. Penny and Lenny can eat a whole gallon of ice cream together in 1 2/3 hours. All three together can eat a whole gallon of ice cream together in 1 hour. How many hours would it take Jenny to eat a whole gallon of ice cream all by herself?
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Algebra.Com's Answer #589392 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Jenny and Penny can eat a whole gallon of ice cream together in 2 hours. Penny and Lenny can eat a whole gallon of ice cream together in 1 2/3 hours. All three together can eat a whole gallon of ice cream together in 1 hour. How many hours would it take Jenny to eat a whole gallon of ice cream all by herself? \n" ); document.write( "================= \n" ); document.write( "Use a set of equations of rates to get: \n" ); document.write( "j + p = 1/2 job/hr \n" ); document.write( "p + L = 3/5 job/hr \n" ); document.write( "j + p + L = 1/1 job/hr \n" ); document.write( "------------------------------ \n" ); document.write( "Substitute for \"j\" and for \"L\" and solve for \"p\":: \n" ); document.write( "(1/2)-p + p + (3/5)-p = 1 \n" ); document.write( "Simplify:: \n" ); document.write( "(1/2)+(3/5) - p = 1 \n" ); document.write( "----- \n" ); document.write( "(5+6)/10 - p = 1 \n" ); document.write( "-p = -1/10 \n" ); document.write( "p = 1/10 (Penny's rate) \n" ); document.write( "---- \n" ); document.write( "Solve for \"J\" \n" ); document.write( "j + p = 1/2 \n" ); document.write( "j + 1/10 = 1/2 \n" ); document.write( "---- \n" ); document.write( "j = (5/10) - (1/10) \n" ); document.write( "j = 4/10 = 2/5 (Jenny's rate) \n" ); document.write( "------ \n" ); document.write( "Ans:: Jenny's time to do the job alone:: 5/2 = 2 1/2 hrs \n" ); document.write( "-------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "-------------- \n" ); document.write( "------------ \n" ); document.write( " \n" ); document.write( " |