document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=964519>Question 964519</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of rectangle is 5cm less than three times its width. If the area of the rectangle is 22cm^2, find the dimensions of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #589380 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=589380\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of rectangle is 5cm less than three times its width. If the area of the rectangle is 22cm^2, find the dimensions of the rectangle.<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "width = W<BR>\n" );
document.write( "length = 3W-5<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Area = length*width<BR>\n" );
document.write( "22 = W(3W-5)<BR>\n" );
document.write( "3W^2 - 5W - 22 = 0<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "3W^2 - 11W+6W - 22 = 0<BR>\n" );
document.write( "W(3W-11)+2(3W-11) = 0<BR>\n" );
document.write( "(3W-11)(W+2) = 0<BR>\n" );
document.write( "Positive solution:<BR>\n" );
document.write( "W = 11/3 = 3 1/3 cm (width)<BR>\n" );
document.write( "L = 3(11/3)-5 = 11-5 = 6cm (length)<BR>\n" );
document.write( "----------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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