document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=964428>Question 964428</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has two acid solutions. Solution A contains 10% acid, and Solution B contains 30% acid. He will mix the two solutions to make 10 liters of a third solution, Solution C, containing 25% acid.\r<BR>\n" );
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document.write( "The system of equations shown can be used to represent this situation.\r<BR>\n" );
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document.write( "x + y = 10<BR>\n" );
document.write( "0.10x + 0.30y = 2.5\r<BR>\n" );
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document.write( "What is the number of liters of solution B the chemist mixes with solution A to create solution C containing 25% acid?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #589334 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=589334\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "A=liters of Solution A; B=liters of Solution B<BR>\n" );
document.write( "A+B=10<BR>\n" );
document.write( "A=10-B Use this to substitute for A<BR>\n" );
document.write( "0.10A+0.30B =0.25(10) Substitute for A from above.<BR>\n" );
document.write( "0.10(10-B)+0.30B=2.5<BR>\n" );
document.write( "1-0.10B+0.30B=2.5 Subtract 1 from each side.<BR>\n" );
document.write( "0.20B=1.5 Multiply each side by 5.<BR>\n" );
document.write( "B=7.5 ANSWER 1:The chemist should use 7.5 liters of solution B.<BR>\n" );
document.write( "A=10-B=10-7.5=2.5 ANSWER 2: The chemist should use 2.5 liters of Solution A.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "0.10(A)+0.30(B)=0.25(10)<BR>\n" );
document.write( "0.10(2.5)+0.30(7.5)=2.5<BR>\n" );
document.write( "0.25+2.25=2.5<BR>\n" );
document.write( "2.5=2.5\r<BR>\n" );
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document.write( " </SPAN>\n" );
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