document.write( "Question 964315: I don't know where else to turn, I've asked my tutors my teacher and peers to explain how to graph sin,cos,sec,csc,tan,cot with phase shifts but nothing seems to work or I am just stupid...how do I set them up? my main confusing is all to do with the phase shifts, everything else makes sense to me. I know the amp, the periodicity. But it's when it comes to shifting everything right or left where the confusion sets in. The process of doing this is troublesome and I keep hitting brick walls. For instance, my teacher asked us to draw the graph of: y=10tan(3t-pi/8) I know I would rerrange like y=10tan3(t-pi/24) but after that I wouldn't know what to do, I just want to know what the points are going to be on the graph and how to derive them...I am at my witts end here. Please help me understand.\r
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Algebra.Com's Answer #589252 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
The best place to start is to first graph the basic function without any shifting.
\n" ); document.write( "For example, take the tan function your teacher gave you: y=10tan(3t-pi/8)
\n" ); document.write( "This equation takes the form: y=A*tan(Bx-C), A=multiplier, period=π/B, C/B=phase shift
\n" ); document.write( "For your given tan function: period=π/B=π/3
\n" ); document.write( "1/4 period=(π/3)/4=π/12≈0.26
\n" ); document.write( "coordinates for one period: (-π/6, u.d.), (-π/12, -1), (0, 0), (π/12, 1), (π/6, u.d.)
\n" ); document.write( "multiply y-coordinates by 10: (-π/6, u.d.), (-π/12, -10), (0, 0), (π/12, 10), (π/6, u.d.)
\n" ); document.write( "phase shift=C/B=(π/8)/3=π/24 (shift to right)
\n" ); document.write( "coordinates for final configuration: (-3π/24, u.d.), (-π/24, -10), (π/24, 0), (3π/24, 10), (5π/24, u.d.)
\n" ); document.write( "u.d.=undefined
\n" ); document.write( "..
\n" ); document.write( "Form of equation for sin: y= Asin(Bx-C), A=amplitude, Period=2π/B, Phase shift=C/B
\n" ); document.write( "Form of equation for cos: y= Acos(Bx-C), A=amplitude, Period=2π/B, Phase shift=C/B
\n" ); document.write( "note: this is just one of the ways I do it. There may be other ways. Hope this helps.
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