document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=929173>Question 929173</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Brando is 3 lbs heavier than Elliana. Keijay is 6 lbs heavier than Elliana, If you add up their weight, you will get 159. How heavy is Keijay? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #589213 by </B><A HREF=/tutors/aboutme.mpl?userid=EdenWolf><B>EdenWolf(517)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=EdenWolf><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=EdenWolf><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=589213\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = Elliana's weight, x+3=Brando's weight, and x + 6 = Keijay's weight. Set up an equation.<BR>\n" );
document.write( "x+x+3+x+6=159<BR>\n" );
document.write( "Solve for x.<BR>\n" );
document.write( "3x+3+6=159<BR>\n" );
document.write( "3x+9=159<BR>\n" );
document.write( "3x=150<BR>\n" );
document.write( "x=50\r<BR>\n" );
document.write( "\n" );
document.write( "Now add 6 to 50 to get 56. So Keijay's weight is 56 lbs.<BR>\n" );
document.write( " </SPAN>\n" );
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