document.write( "Question 964272: the length of a rectangle is 8 inches more than its width if 4 inches are taken from the length and added to the with the future becomes the square with an area of 121 square inches what are the dimensions of the original figure \n" ); document.write( "

Algebra.Com's Answer #589146 by macston(5194) $\"\"$ $\"About$

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W=width; L=length=W+8in
\n" ); document.write( "For square: side=W+4
\n" ); document.write( " $\"%28W%2B4%29%5E2=A\"$
\n" ); document.write( " $\"W%5E2%2B8W%2B16=121in%5E2\"$
\n" ); document.write( " $\"W%5E2%2B8W-105in%5E2=0\"$
\n" ); document.write( " $\"%28W-7%29%28W%2B15%29=0\"$
\n" ); document.write( " $\"W-7=0\"$ $\"or\"$ $\"W%2B15=0\"$
\n" ); document.write( " $\"W=7\"$ $\"or\"$ $\"W=-15\"$
\n" ); document.write( "ANSWER 1: The width is 7 inches.
\n" ); document.write( "L=W+8in=7in+8in=15 in
\n" ); document.write( "ANSWER 2: The length is 15 inches.
\n" ); document.write( "CHECK:
\n" ); document.write( " $\"%28L-4in%29%28W%2B4in%29=121in%5E2\"$
\n" ); document.write( " $\"15in-4in%29%287in%2B4in%29=121in%5E2\"$
\n" ); document.write( " $\"%2811in%29%2811in%29=121in%5E2\"$
\n" ); document.write( " $\"121in%5E2=121in%5E2\"$
\n" ); document.write( " \n" ); document.write( "

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