document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=82229>Question 82229</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help.<BR>\n" );
document.write( "The length of a rectangle in 9in. more than twice its width. If the peremiter of the rectangle is 48in.,find the width of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #58914 by </B><A HREF=/tutors/aboutme.mpl?userid=neta><B>neta(14)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=neta><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=58914\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the eqn for the problem is \r<BR>\n" );
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document.write( "let the width be x, the perimeter is give as 48<BR>\n" );
document.write( "perimeter=2(l+b)<BR>\n" );
document.write( "therefor L=9+2x<BR>\n" );
document.write( "48=2((2x+9)+x)<BR>\n" );
document.write( "48=4x+18+2x<BR>\n" );
document.write( "take 18 over<BR>\n" );
document.write( "48-18=6x<BR>\n" );
document.write( "30=6x<BR>\n" );
document.write( "x=30/6<BR>\n" );
document.write( "x=5<BR>\n" );
document.write( "therefore the width is 5in.<BR>\n" );
document.write( "if you doubt your answer you cn always fix it back to the eqn to test your answer </SPAN>\n" );
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