document.write( "Question 964049: The Linear equation for a company that sells plastic airtight containers is P= a+bx, where P is the profit in Rands, x is the number of units sold, and a andb are constants. When 100 units are sold, the profit is R21 000 and when 450 units are sold, the profit is R126 000.\r
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document.write( "Determine the values if a and b.\r
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document.write( "Draw a neat graph showing profit as a function of the number of units sold.\r
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Algebra.Com's Answer #589130 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The Linear equation for a company that sells plastic airtight containers is \n" ); document.write( " P= a+bx, where \n" ); document.write( " P is the profit in Rands, \n" ); document.write( " x is the number of units sold, \n" ); document.write( " and a and b are constants. \n" ); document.write( ": \n" ); document.write( " When 100 units are sold, the profit is R21 000 \n" ); document.write( "a + 100b = 21000 \n" ); document.write( " and when 450 units are sold, the profit is R126 000. \n" ); document.write( "a + 450b = 126000 \n" ); document.write( ": \n" ); document.write( "Determine the values if a and b. \n" ); document.write( "Subtract the 1st equation from the 2nd equation \n" ); document.write( "a + 450b = 126000 \n" ); document.write( "a + 100b = 21000 \n" ); document.write( "------------------Eliminates a, find b \n" ); document.write( "0 + 350b = 105000 \n" ); document.write( "b = 105000/350 \n" ); document.write( "b = 300 \n" ); document.write( "Find a using the 1st equation \n" ); document.write( "a + 100(300) = 21000 \n" ); document.write( "a + 30000 = 21000 \n" ); document.write( "a = 21000 - 30000 \n" ); document.write( "a = -9000 \n" ); document.write( ": \n" ); document.write( "The equation P = 300x - 9000 \n" ); document.write( "Draw a neat graph showing profit as a function of the number of units sold. \n" ); document.write( " |