document.write( "Question 964193: Please help solve this equation
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document.write( "I know you should isolate the radical so you add sqrt(x-2) to 3 it becomes:
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document.write( " and you then get rid of the radical so you have to square both side and then it cancles the radical. Now it's 2x+5=3+sqrt(x-2)^2 and then it's: 2x+5=3+sqrt(x-2)*3+sqrt(x-2) which equals: 2x+5=9+3sqrt(x-2)+3sqrt(x-2)+sqrt(x-2)^2 which cancels out and is just x-2.now we just combine like terms: 2x+5=7+6sqrt(x-2)+x now subtract 7 and x to 2x+5 and you get: x-2=6sqrt(x-2) and that's where I'm stuck I know you have to divide by 6 for both sides to isolate the radical and then square again but then what?I know the answer is x=2 and x=38 but how do you get it? \n" );
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Algebra.Com's Answer #589085 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Square BOTH sides. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Isolate the resulting radical. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Square both sides again. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1904=16*119\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(Possible mistake in this work) \n" ); document.write( " |