document.write( "Question 964189: I need help with this question: The area of a rectangular rug is 160sqft. if it's width is 2ft less than 1/2 it's length, find the dimensions of the rug.
\n" ); document.write( "I know A=LW. I'm racking my brain, but this is not my area of expertise. The equation I wrote to find the W is W=L/2-2. then i wrote 160=L(L/2-2), but that isn't getting me anywhere. I need help figuring out how to write the equation to find the dimensions. PLEASE HELP! :-) \n" ); document.write( "

Algebra.Com's Answer #589074 by Alan3354(69443) $\"\"$ $\"About$

You can put this solution on YOUR website!
The area of a rectangular rug is 160sqft. if it's [sic] width is 2ft less than 1/2 it's [sic] length, find the dimensions of the rug.
\n" ); document.write( "I know A=LW. I'm racking my brain, but this is not my area of expertise. The equation I wrote to find the W is W=L/2-2. then i wrote 160=L(L/2-2)
\n" ); document.write( "===================
\n" ); document.write( "160=L(L/2-2)
\n" ); document.write( "Your eqn is correct, just solve it.
\n" ); document.write( "320 = L*(L-4)
\n" ); document.write( "L^2 - 4L - 320 = 0
\n" ); document.write( "(L - 20)*(L + 16) = 0
\n" ); document.write( "Ignore the L = -16
\n" ); document.write( "---
\n" ); document.write( "L = 20
\n" ); document.write( "W = 8
\n" ); document.write( "==================
\n" ); document.write( "PS it's = it is \n" ); document.write( "

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