document.write( "Question 964189: I need help with this question: The area of a rectangular rug is 160sqft. if it's width is 2ft less than 1/2 it's length, find the dimensions of the rug.
\n" ); document.write( "I know A=LW. I'm racking my brain, but this is not my area of expertise. The equation I wrote to find the W is W=L/2-2. then i wrote 160=L(L/2-2), but that isn't getting me anywhere. I need help figuring out how to write the equation to find the dimensions. PLEASE HELP! :-)
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Algebra.Com's Answer #589073 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Try to work with mostly lower cased letters for the variables.\r
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\n" ); document.write( "\n" ); document.write( "w, width
\n" ); document.write( "L, length (upper case so not to confuse with any digit 1).
\n" ); document.write( "A, area of the rug\r
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\n" ); document.write( "\n" ); document.write( "You already know, \"A=L%2Aw\".
\n" ); document.write( "Translate the description into symbolism.\r
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\n" ); document.write( "\n" ); document.write( "\"A=160\";
\n" ); document.write( "\"wL=160\";
\n" ); document.write( "\"w=-2%2B%281%2F2%29L\".\r
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\n" ); document.write( "\n" ); document.write( "What do you have?
\n" ); document.write( "Basically two equations in the two unknown variables, w and L. Use simple substitution.\r
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\n" ); document.write( "\n" ); document.write( "\"system%28wL=160%2Cw=L%2F2-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28L%2F2-2%29L=160\"
\n" ); document.write( "At this point you should no longer be \"racking\" your brain, because you now have a quadratic equation in one single variable, L. You already found this far and then asked for help.
\n" ); document.write( "\"highlight_green%28L%5E2%2F2-2L=160%29\"
\n" ); document.write( "\"2%28L%5E2%2F2-2L%29=2%2A160\"
\n" ); document.write( "\"L%5E2-4L=320\"
\n" ); document.write( "\"highlight_green%28L%5E2-4L-320=0%29\"
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\n" ); document.write( "Not even trying to factor that, ....
\n" ); document.write( "discriminant is \"%28-4%29%5E2-4%2A1%2A%28-320%29=16%2B1280=highlight_green%281296=%2836%29%5E2%29\".
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\n" ); document.write( "General solution for quadratic equation:
\n" ); document.write( "\"L=%284%2B-+sqrt%2836%5E2%29%29%2F2\"
\n" ); document.write( "\"L=%284%2B-+36%29%2F2\"
\n" ); document.write( "Obviously the PLUS-form makes sense only.
\n" ); document.write( "\"L=%284%2B36%29%2F2\"
\n" ); document.write( "\"L=40%2F2\"
\n" ); document.write( "\"highlight%28L=20%29\".\r
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\n" ); document.write( "\n" ); document.write( "Use either the area equation OR the description's formula equation to find w.
\n" ); document.write( "\"wL=160\"
\n" ); document.write( "\"w=160%2FL\"
\n" ); document.write( "\"w=160%2F20\"
\n" ); document.write( "\"highlight%28w=8%29\"
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