document.write( "Question 963958: Sam had a piggy bank full of nickels and dimes. He added up all the money and it was 123 coins worth $8.20. How many dimes did he have? \n" ); document.write( "
Algebra.Com's Answer #589054 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "N=nickels; D=dimes \n" ); document.write( "N+D=123 \n" ); document.write( "D=123-N Use this to substitute for D. \n" ); document.write( "$0.05N+$0.10D=$8.20 Substitute for D from above. \n" ); document.write( "$0.05N+$0.10(123-N)=$8.20 \n" ); document.write( "$0.05N+$12.30-$0.10N=$8.20 Subtract $12.30 from each side. \n" ); document.write( "-$0.05N=-$4.10 Divide each side by $0.05. \n" ); document.write( "N=82 There were 82 nickels. \n" ); document.write( "D=123-N=123-82=41 ANSWER: There were 41 dimes. \n" ); document.write( "CHECK: \n" ); document.write( "$0.05N+$0.10D=$8.20 \n" ); document.write( "$0.05(82)+$0.10(41)=$8.20 \n" ); document.write( "$4.10+$4.10=$8.20 \n" ); document.write( "$8.20=$8.20 \n" ); document.write( " |